9=b^2/3

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Solution for 9=b^2/3 equation: 


b in (-oo:+oo)

9 = (b^2)/3 // - (b^2)/3

9-((b^2)/3) = 0

-1/3*b^2 = -9 // : -1/3

b^2 = 27

b^2 = 27 // ^ 1/2

abs(b) = 3*3^(1/2)

b = 3*3^(1/2) or b = -(3*3^(1/2))

b in { 3*3^(1/2), -(3*3^(1/2)) }

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